Question:
Four identical solid spheres each of mass 'm' and radius 'a' are placed with their centres on the four corners of a square of side ' $b$ '. The moment of inertia of the system about one side of square where the axis of rotation is parallel to the plane of the square is :
Correct Option: , 3
Solution:
$\mathrm{I}=2 \times\left(\frac{2}{5} \mathrm{ma}^{2}\right)+2 \times\left(\frac{2}{5} \mathrm{ma}^{2}+\mathrm{mb}^{2}\right)$
$\mathrm{I}=\frac{8}{5} m \mathrm{a}^{2}+2 m b^{2}$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.