How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?

Question:

How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?

Solution:

Total number of arrangements of 9 digits, taken 3 at a time = 9P3

∴ Total 3-digit numbers that can be formed by using the digits 1 to 9, if no digit is repeated = 9P3 = 9×">××8×">××7 = 504  

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