If a semiconductor photodiode can detect a photon

Question:

If a semiconductor photodiode can detect a photon with a maximum wavelength of $400 \mathrm{~nm}$, then its band gap energy is:

  1. $2.0 \mathrm{eV}$

  2. $1.5 \mathrm{eV}$

  3. $3.1 \mathrm{eV}$

  4. $1.1 \mathrm{eV}$


Correct Option: , 3

Solution:

$\Delta \mathrm{E}=\frac{\lambda \mathrm{c}}{\lambda \mathrm{e}}=3 . \mathrm{leV}$

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