If E¯¯¯ denote the complement or negation of an even E, what is the value of P(E) + P(E¯¯¯) ?

Question:

If $\bar{E}$ denote the complement or negation of an even $E$, what is the value of $P(E)+P(\bar{E})$ ?

Solution:

Given: $\bar{E}$ denotes the complement or negation of an event $E$.

TO FIND: $P(E)+P(\bar{E})$

CALCULATION: We know that sum of probability of occurrence of an event and probability of non occurrence of an event is $1 .$

Hence $P(E)+P(E)=1$

Hence $P(E)+P(E)=1$

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