If the angle of elevation of a tower from a distance of 100 metres from its foot is 60°

Let  be the height of tower is meters

Given that: angle of elevation is from tower of foot and distance meters.

Here, we have to find the height of tower.

So we use trigonometric ratios.

In a triangle,

$\Rightarrow \tan C=\frac{A B}{B C}$

$\Rightarrow \tan 60^{\circ}=\frac{A B}{B C}$

$\Rightarrow \sqrt{3}=\frac{h}{100}$

$\Rightarrow h=100 \sqrt{3}$

Hence correct option is a.