Question:
If the magnetic field of a plane electromagnetic wave is given by (The speed of light $=3 \times 10^{8} \mathrm{~m} / \mathrm{s}$ )
$\mathrm{B}=100 \times 10^{-6} \sin \left[2 \pi \times 2 \times 10^{15}\left(\mathrm{t}-\frac{x}{\mathrm{c}}\right)\right]$
then the maximum electric field associated with it is:
Correct Option: , 2
Solution:
(2) Using, formula $\mathrm{E}_{0}=\mathrm{B}_{0} \times \mathrm{C}$
$=100 \times 10^{-6} \times 3 \times 10^{8}$
$=3 \times 10^{4} \mathrm{~N} / \mathrm{C}$
Here we assumed that
$\mathrm{B}_{0}=100 \times 10^{-6}$ is in tesla $(\mathrm{T})$ units
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