If the system of linear equations

Question:

If the system of linear equations 

2x + 2y + 3z = a

3x – y + 5z = b

x – 3y + 2z = c 

where a, b, c are non-zero real numbers, has more then one solution, then :

  1. b – c – a = 0

  2. a + b + c = 0 

  3. b + c – a = 0

  4. b – c + a = 0 


Correct Option: 1

Solution:

$P_{1}: 2 x+2 y+3 z=a$

$P_{2}: 3 x-y+5 z=b$

$P_{3}: x-3 y+2 z=c$

We find

$\mathrm{P}_{1}+\mathrm{P}_{3}=\mathrm{P}_{2} \Rightarrow \mathrm{a}+\mathrm{c}=\mathrm{b}$

Leave a comment