Question:
If then find values of x, y, z and w.
$\left[\begin{array}{cc}x y & 4 \\ z+6 & x+y\end{array}\right]=\left[\begin{array}{cc}8 & w \\ 0 & 6\end{array}\right]$
Solution:
In the given matrix equation,
Comparing the corresponding elements, we get
x + y = 6,
xy = 8,
z + 6 = 0 and
w = 4
From the first two equations, we have
(6 – y) . y = 8
y2 – 6y + 8 = 0
(y – 2) (y – 4) = 0
y = 2 or y = 4
Hence, x = 4 and x = 2
Also, z + 6 = 0
z = -6 and w = 4
Therefore,
x = 2, y = 4 or x = 4, y = 2, z = -6 and w = 4
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.