Question:
If |x – 1| ≤ 2 then –1 _______ x < 3.
Solution:
If |x – 1| ≤ 2
i.e. –2 ≤ x – 1 ≤ 2 (By defination of modulus inequality)
Now, By adding 1 throught the inequality,
We get,
–2 + 1 ≤ x – 1 + 1 ≤ 2 + 1
i.e –1 ≤ x ≤ 3
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