If x and y are integers
Question:
If $x$ and $y$ are integers such that $x^{2}>y^{2}$, then $x^{3}>y^{3}$.
Solution:
False
Suppose, $-1$ and $-2$ are integers
Then, $(-2)^{2^{\prime}}>(-1)^{2}=4>1$
and $(-2)^{3}<(-1)^{3}=-8<-1$