In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays. Find the probability that:

Question:

In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays. Find the probability that:

1. He hit a boundary

2. He did not hit a boundary.

Solution:

Number of times the batsman hits a boundary = 6

Total number of balls played = 30

Number of times the batsman did not hit a boundary = 30 - 6 = 24

1. Probability that the batsman hits a boundary

$=\frac{\text { Number of times hehita boundary }}{\text { Total no of balls }}$

= 6/30

= 15

2. Probability that the batsman does not hit a boundary

$=\frac{\text { Number of time he did not hita boundary }}{\text { Total no of balls }}$

= 24/30

= 4/5

 

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