Question:
In a Young's double slit experiment, light of $500 \mathrm{~nm}$ is used to produce an interference pattern. When the distance between the slits is $0.05 \mathrm{~mm}$, the angular width (in degree) of the fringes formed on the distance screen is close to :
Correct Option: , 4
Solution:
$\Delta \theta_{0}=\left(\frac{\lambda}{\mathrm{d}} \times \frac{180}{\pi}\right)^{0}$
$=0.57^{\circ}$
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