In a Young's double slit experiment, slits are separated by

Question:

In a Young's double slit experiment, slits are separated by $0.5 \mathrm{~mm}$, and the screen is placed $150 \mathrm{~cm}$ away. A beam of light consisting of two wavelengths, $650 \mathrm{~nm}$ and $520 \mathrm{~nm}$, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide is :-

  1. $9.75 \mathrm{~mm}$

  2. $15.6 \mathrm{~mm}$

  3.  $1.56 \mathrm{~mm}$

  4. $7.8 \mathrm{~mm}$


Correct Option: , 4

Solution:

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now