In Freundlich adsorption isotherm, slope of AB line is :

$\log n$ with $(n>1)$

$\mathrm{n}$ with $(\mathrm{n}, 0.1$ to $0.5)$

$\log \frac{1}{n}$ with $(n<1)$

$\frac{1}{\mathrm{n}}$ with $\left(\frac{1}{\mathrm{n}}=0\right.$ to 1$)$