In the circuit shown here, the point ' C ' is kept connected to point ' A '

Question:

In the circuit shown here, the point ' $\mathrm{C}$ ' is kept connected to point ' $\mathrm{A}$ ' till the current flowing through the circuit becomes constant. Afterward, suddenly, point ' $C$ ' is disconnected from point ' $A$ ' and connected to point ' $B$ ' at time $t=0$. Ratio of the voltage across resistance and the inductor at $\mathrm{t}=\mathrm{L} /$ R will be equal to:

  1. $-1$

  2. $\frac{1-e}{e}$

  3. $\frac{e}{1-e}$

  4. 1


Correct Option: 1

Solution:

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