Question:
Let $A=\{1,2,3,4\}$ and $f: A \rightarrow A$ be given by $f=\{(1,4),(2,3),(3,2),(4,1)\}$. Then $f^{-1}=$
Solution:
Given: A function $f: A \rightarrow A$ be given by $f=\{(1,4),(2,3),(3,2),(4,1)\}$
$f=\{(1,4),(2,3),(3,2),(4,1)\}$
$\Rightarrow f^{-1}=\{(4,1),(3,2),(2,3),(1,4)\}$
Thus, $f^{-1}=\{(4,1),(3,2),(2,3),(1,4)\}$
Hence, $f^{-1}=\{(4,1),(3,2),(2,3),(1,4)\}$.
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