Question:
Let A and B be two sets such that n(A) = 3 and n(B) = 2.
If $a \neq b \neq c$ and $(a, 0),(b, 1),(c, 0)$ is in $A \times B$, find $A$ and $B$.
Solution:
Since, (a, 0), (b, 1), (c, 0) are the elements of A × B.
$\therefore a, b, c \in A$ and $0,1 \in B$
It is given that $n(A)=3$ and $n(B)=2$
$\therefore a, b, c \in A$ and $n(A)=3$
$\Rightarrow A=\{a, b, c\}$
and 0, 1 Є B and n(B) = 2
⇒ B = {0, 1}
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