Locate 8–√ on the number line.


Locate $\sqrt{8}$ on the number line.



To represent $\sqrt{8}$ on the number line, follow the following steps of construction:

(i) Mark points 0 and 2 as $O$ and $B$, respectively.

(ii) At point $B$, draw $A B \perp O A$ such that $A B=2$ units.

(iii) Join OA.

(iv) With $O$ as centre and radius $O A$, draw an arc intersecting the number line at point $P$.

Thus, point P represents $\sqrt{8}$ on the number line.


In right $\triangle \mathrm{OAB}$,

Using Pythagoras theorem,






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