Mark against the correct answer in each of the following:

Question:

Mark $(\sqrt{ })$ against the correct answer in each of the following:

$\int \frac{\sqrt{16+(\log x)^{2}}}{x} d x=?$

A. $\frac{1}{2} \log x \cdot \sqrt{16+(\log x)^{2}}+8 \log \left|\log x+\sqrt{16+(\log x)^{2}}\right|+C$

B. $\frac{1}{2} \log x \cdot \sqrt{16+(\log x)^{2}}+4 \log \left|\log x+\sqrt{16+(\log x)^{2}}\right|+C$

C. $\log x \cdot \sqrt{16+(\log x)^{2}}+16 \log \left|\log x+\sqrt{16+(\log x)^{2}}\right|+C$

D. none of these

Solution:

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