Mark against the correct answer in the following:

Question:

Mark $(\sqrt{)}$ against the correct answer in the following:

The solution of the $\mathrm{DE} \frac{\mathrm{dy}}{\mathrm{dx}}=1-x+y-x y$ is

A. $\log (1+y)=x-\frac{x^{2}}{2}+C$

B. $e^{(1+y)}=x-\frac{x^{2}}{2}+C$

C. $\mathrm{e}^{\mathrm{y}}=\mathrm{x}-\frac{\mathrm{x}^{2}}{2}+\mathrm{C}$

D. None of these

Solution:

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