Mark against the correct answer in the following:

Question:

Mark $(\sqrt{)}$ against the correct answer in the following:

The general solution of the $D E \log \left(\frac{d y}{d x}\right)=(a x+b y)$ is

A. $\frac{-e^{-b y}}{b}=\frac{e^{a x}}{a}+C$

B. $e^{a x}-e^{-b y}=C$

C. $b e^{a x}+a e^{b y}=C$

D. None of these

Solution:

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