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Minimise $Z=x+2 y$

subject to $2 x+y \geq 3, x+2 y \geq 6, x, y \geq 0$.


The feasible region determined by the constraints, 2x + y ≥ 3, x + 2y ≥ 6, x ≥ 0, and y ≥ 0, is as follows.

The corner points of the feasible region are A (6, 0) and B (0, 3).

The values of Z at these corner points are as follows.

It can be seen that the value of Z at points A and B is same. If we take any other point such as (2, 2) on line x + 2y = 6, then Z = 6

Thus, the minimum value of Z occurs for more than 2 points.

Therefore, the value of Z is minimum at every point on the line, x + 2y = 6

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