Question:
An electron (mass m) with an initial velocity is in an electric field . If λ0 = h/mv0, it’s de Broglie wavelength at time t is given by
(a) λ0
(b)
$\lambda_{0} \sqrt{1+\frac{e^{2} E_{0}^{2} t^{2}}{m^{2} v_{0}^{2}}}$
(c)
$\frac{\lambda_{0}}{\sqrt{1+\frac{e^{2} E_{0}^{2} t^{2}}{m^{2} v_{0}^{2}}}}$
(d)
$\frac{\lambda_{0}}{1+\frac{e^{2} E_{0}^{2} t^{2}}{m^{2} v_{0}^{2}}}$
Solution:
The correct answer is c) $\frac{\lambda_{0}}{\sqrt{1+\frac{e^{2} E_{0}^{2} t^{2}}{m^{2} v_{0}^{2}}}}$
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