Question:
Pressure inside two soap bubbles are $1.01$ and $1.02$ atmosphere, respectively. The ratio of their volumes is :
Correct Option: 1
Solution:
$\mathrm{P}_{1}=0.01=4 \mathrm{~T} / \mathrm{R}_{1}$............(1)
$\mathrm{P}_{2}=0.02=4 \mathrm{~T} / \mathrm{R}_{2}$..........(2)
Equation (1) . (2)
$\frac{1}{2}=\frac{\mathrm{R}_{2}}{\mathrm{R}_{1}}$
$\mathrm{R}_{1}=2 \mathrm{R}_{2}$
$\frac{V_{1}}{V_{2}}=\frac{R_{1}^{3}}{R_{2}^{3}}=\frac{8 R_{2}^{3}}{R_{2}^{3}}=8$