prove that

Question:

If $\frac{15}{8}-7 x=9$, then $-7 x=9+\frac{15}{8}$

Solution:

False

Given,  $\frac{15}{8}-7 x=9$

$\Rightarrow$ $-7 x=9-\frac{15}{8}$ $\left[\right.$ transposing $\frac{15}{8}$ to RHS $]$

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