Prove the following

Question:

simplify

(a) (32/5) + (23/11) × (22/15)

(b) (3/7) × (28/15) ÷ (14/5)

(c) (3/7) + (-2/21) × (-5/6)

(d) (7/8) + (1/6) – (1/12)

Solution:

(a) (32/5) + (23/11) × (22/15)

= (32/5) + (23/1) × (2/15)

= (32/5) + (46/15)

= (96 + 46)/15

= 142/15

(b) (3/7) × (28/15) ÷ (14/5)

= (3/7) × (28/15) ÷ (14/5)

= (1/1) × (4/5) ÷ (14/5)

= (4/5) ÷ (14/5)

= (4/5) × (5/14)

= (2/1) × (1/7)

= 2/7

(c) (3/7) + (-2/21) × (-5/6)

= (3/7) – (2/21) × (-5/6)

= (3/7) – (1/21) × (-5/3)

= (3/7) – (-5/63)

= (3/7) + (5/63)

= (27 + 5)/63

= 32/63

(d) (7/8) + (1/6) – (1/12)

= (7/8) + (1/6) – (1/12)

= ((14 + 1)/16) – (1/12)

= (15/16) – (1/12)

= (45-4)/48

= 41/48

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now