Prove the following

Question:

If $\overrightarrow{\mathrm{P}} \times \overrightarrow{\mathrm{Q}}=\overrightarrow{\mathrm{Q}} \times \overrightarrow{\mathrm{P}}$, the angle between $\overrightarrow{\mathrm{P}}$ and $\overrightarrow{\mathrm{Q}}$ is $\theta\left(0^{\circ}<\theta<360^{\circ}\right)$. The value of ' $\theta^{\prime}$ will be_______ $\circ$.

Solution:

$-P Q \sin \theta$

$=P Q \sin \theta$

$\Rightarrow \theta=180^{\circ}$

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