Question:
R is a relation from [11, 12, 13] to [8, 10, 12] defined by y = x − 3. Then, R−1 is
(a) [(8, 11), (10, 13)]
(b) [(11, 8), (13, 10)]
(c) [(10, 13), (8, 11), (12, 10)]
(d) none of these
Solution:
(a) [(8, 11), (10, 13)]
R is a relation from [11, 12, 13] to [8, 10, 12], defined by y = x − 3
Now, we have:
$11-3=8$
$13-3=10$
So, R = {(13,10),(11,8)}
∴ R−1 = {(10,13),(8,11)}
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.