Question:
sin (45° + θ) – cos (45° – θ) is equal to
(a) 2 cosθ
(b) 0
(c) 2 sinθ
(d) 1
Solution:
(b) sin(45° + θ) – cos(45° – θ) = cos[90°- (45° + θ)] – cos(45°- 6) [∴ cos(90° – θ) = sin0]
= cos (45° – 0) – cos (45° – 0)
= 0
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