Solve the following :


A particle of mass $100 \mathrm{~g}$ is kept on the surface of a uniform sphere of mass $10 \mathrm{~kg}$ and radius $10 \mathrm{~cm}$. Find the work to be done against the gravitational force between them to take the particle away from the sphere.


Work done against gravitational force $=$ change in potential energy


$W=0-\left(-\frac{G M m}{r}\right)$

$W=\frac{G M m}{r}=\frac{6.67 \times 10^{-11} \times 0.1 \times 10}{0.1}$

$W=6.67 \times 10^{-10} \mathrm{~J}$

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