(i) Which term of the A.P. 3, 8, 13, ... is 248?
(ii) Which term of the A.P. 84, 80, 76, ... is 0?
(iii) Which term of the A.P. 4, 9, 14, ... is 254?
(i) 3, 8, 13...
Here, we have:
a = 3
$d=(8-3)=5$
Let $a_{n}=248$
$\Rightarrow a+(n-1) d=248$
$\Rightarrow 3+(n-1) 5=248$
$\Rightarrow(n-1) 5=245$
$\Rightarrow n-1=49$
$\Rightarrow n=50$
Hence, 248 is the 50th term of the given A.P.
(ii) 84, 80, 76...
Here, we have:
a = 84
$d=(80-84)=-4$
Let $a_{n}=0$
$\Rightarrow a+(n-1) d=0$
$\Rightarrow 84+(n-1)(-4)=0$
$\Rightarrow(n-1)(-4)=-84$
$\Rightarrow(n-1)=21$
$\Rightarrow n=22$
Hence, 0 is the 22nd term of the given A.P.
(iii) 4, 9, 14...
Here, we have:
a = 4
$d=(9-4)=5$
Let $a_{n}=254$
$\Rightarrow a+(n-1) d=254$
$\Rightarrow 4+(n-1) 5=254$
$\Rightarrow(n-1) 5=250$
$\Rightarrow(n-1)=50$
$\Rightarrow n=51$
Hence, 254 is the 51st term of the given A.P.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.