Solve the following equation and verify your answer:
$\frac{2}{3 x}-\frac{3}{2 x}=\frac{1}{12}$
$\frac{2}{3 x}-\frac{3}{2 x}=\frac{1}{12}$
or, $\frac{4-9}{6 x}=\frac{1}{12}$
or, $\frac{-5}{x}=\frac{1}{2}$
or, $\mathrm{x}=-10[$ After $c$ ross multiplication $]$
Thus, $x=-10$ is the solution of the given equation.
Check :
Substituting $\mathrm{x}=-10$ in the given equation, we get:
L.H.S. $=\frac{2}{3(-10)}-\frac{3}{2(-10)}=\frac{2}{-30}-\frac{3}{-20}=\frac{4-9}{-60}=\frac{-5}{-60}=\frac{1}{12}$
R.H.S. $=\frac{1}{12}$
$\therefore \mathrm{L} . \mathrm{H} . \mathrm{S} .=\mathrm{R} . \mathrm{H} . \mathrm{S} .$ for $\mathrm{x}=-10$.
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