Solve the following equations

Question:

If $\left[\begin{array}{cc}x-y & z \\ 2 x-y & \omega\end{array}\right]=\left[\begin{array}{rr}-1 & 4 \\ 0 & 5\end{array}\right]$, find $x, y, z$ 우$\omega$

Solution:

Given : $\left[\begin{array}{cc}x-y & z \\ 2 x-y & w\end{array}\right]=\left[\begin{array}{cc}-1 & 4 \\ 0 & 5\end{array}\right]$

Since all the corresponding elements of a matrix are equal,

$x-y=-1$

$\Rightarrow x=-1+y$       ....(1)

$2 x-y=0$                          .....(2)

Putting the value of $x$ in eq. (2), we get

$2(-1+y)-y=0$

$\Rightarrow-2+2 y-y=0$

$\Rightarrow-2+y=0$

$\Rightarrow y=2$

Putting the value of $y$ in eq. (1), we get

$x=-1+2$

$\Rightarrow x=1$

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