Solve the given inequality for real x:
Question:

Solve the given inequality for real x$\frac{1}{2}\left(\frac{3 x}{5}+4\right) \geq \frac{1}{3}(x-6)$

Solution:

$\frac{1}{2}\left(\frac{3 x}{5}+4\right) \geq \frac{1}{3}(x-6)$

$\Rightarrow 3\left(\frac{3 x}{5}+4\right) \geq 2(x-6)$

$\Rightarrow \frac{9 x}{5}+12 \geq 2 x-12$

$\Rightarrow 12+12 \geq 2 x-\frac{9 x}{5}$

$\Rightarrow 24 \geq \frac{10 x-9 x}{5}$

$\Rightarrow 24 \geq \frac{x}{5}$

$\Rightarrow 120 \geq x$

Thus, all real numbers $x$, which are less than or equal to 120 , are the solutions of the given inequality.

Hence, the solution set of the given inequality is $(-\infty, 120]$.

 

 

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