Solve this

Question:

If $\left[\begin{array}{cc}2 x+y & 3 y \\ 0 & 4\end{array}\right]=\left[\begin{array}{ll}6 & 0 \\ 6 & 4\end{array}\right]$, then find $x$

Solution:

The corresponding elements of two equal matrices are equal.

Given : $\left[\begin{array}{cc}2 x+y & 3 y \\ 0 & 4\end{array}\right]=\left[\begin{array}{ll}6 & 0 \\ 6 & 4\end{array}\right]$

$2 x+y=6 \quad \ldots(1)$

$3 y=0$

 

$\Rightarrow y=0$

Putting the value of $y$ in eq. (1)

$2 x+0=6$

$\Rightarrow 2 x=6$

$\Rightarrow x=\frac{6}{2}$

 

$\therefore x=3$

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