$\lim _{x \rightarrow 0} \frac{(27+x)^{1 / 3}-3}{9-(27+x)^{2 / 3}}$ equals :
$-\frac{1}{3}$
$\frac{1}{6}$
$-\frac{1}{6}$
$\frac{1}{3}$
Correct Option: , 3
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