Question: Let $\mathrm{f}:(-1,1) \rightarrow \mathrm{R}$ be a differentiable function with $\mathrm{f}(0)=-1$ and $\mathrm{f}^{\prime}(0)=1$. Let $\mathrm{g}(\mathrm{x})=[\mathrm{f}(2 \mathrm{f}(\mathrm{x})+$ 2)] $]^{2}$. Then $g^{\prime}(0)$ :
Correct Option: , 2
Solution:
