Solve this following

Question:

If $x=\sqrt{2^{\operatorname{cosec}^{-1} t}}$ and $y=\sqrt{2^{\sec ^{-1} t}}(|t| \geq 1)$, then $\frac{d y}{d x}$ is equal to :

 

  1. $-\frac{y}{x}$

  2. $\frac{9}{1+9 x^{3}}$

  3. $-\frac{x}{y}$

  4. $\frac{y}{x}$


Correct Option: 1

Solution:

Solution not required

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