Question:
Given $\mathrm{P}(\mathrm{x})=\mathrm{x}^{4}+\mathrm{ax}^{3}+b \mathrm{x}^{2}+\mathrm{cx}+\mathrm{d}$ such that $\mathrm{x}=0$ is the only real root of $\mathrm{P}^{\prime}(\mathrm{x})=0$. If $\mathrm{P}(-1)<\mathrm{P}(1)$, then in the interval $[-1,1]$ :-
Correct Option: , 4
Solution:
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