Solve this following

Question:

Mark $(\sqrt{)}$ against the correct answer in the following:

If $y=x^{2} \sin \frac{1}{x}$ then $\frac{d y}{d x}=?$

A. $x \sin \frac{1}{x}-\cos \frac{1}{x}$

B. $-\cos \frac{1}{x}+2 x \sin \frac{1}{x}$

C. $-x \sin \frac{1}{x}+\cos \frac{1}{x}$

D. None of these

Solution:

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