Question:
Mark $(\sqrt{)}$ against the correct answer in the following:
If $y=x^{2} \sin \frac{1}{x}$ then $\frac{d y}{d x}=?$
A. $x \sin \frac{1}{x}-\cos \frac{1}{x}$
B. $-\cos \frac{1}{x}+2 x \sin \frac{1}{x}$
C. $-x \sin \frac{1}{x}+\cos \frac{1}{x}$
D. None of these
Solution:
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