Solve this following

Question:

Mark $(\sqrt{ })$ against the correct answer in the following:

If $y=\cos ^{-1}\left(4 x^{3}-3 x\right)$ then $\frac{d y}{d x}=$ ?

A. $\frac{3}{\sqrt{1-x^{2}}}$

B. $\frac{-3}{\sqrt{1-\mathrm{x}^{2}}}$

C. $\frac{4}{\sqrt{1-x^{2}}}$

D. $\frac{4}{\left(3 x^{2}-1\right)}$

Solution:

$\frac{\mathrm{dy}}{\mathrm{dx}}=\frac{-3}{\sqrt{1-\mathrm{x}^{2}}}$

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