Question:
$10.30 \mathrm{mg}$ of $\mathrm{O}_{2}$ is dissolved into a liter of sea water of density $1.03 \mathrm{~g} / \mathrm{mL}$. The concentration of $\mathrm{O}_{2}$ in ppm is
Solution:
$\mathrm{ppm}=\frac{10.3 \times 10^{-3}}{1030} \times 10^{6}=10$
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