Solve this following
Question:
The $\mathrm{pH}$ of a $0.02 \mathrm{M} \mathrm{NH}$ [given $\mathrm{K}_{\mathrm{b}}\left(\mathrm{NH}_{4} \mathrm{OH}\right)=10^{-5}$ and $\log 2=0.301$ ]
Correct Option: , 2
Solution:
