Question:
Ten coins are tossed. What is the probability of getting at least 8 heads?
Solution:
Here we have, n = 10, p = ½ and q = 1 – ½ = ½
P(X ≥ 8) = P(x = 8) + P(x = 9) + P(x = 10)
Therefore, the required probability is 7/128.
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