Question:
The 2nd term of an AP is 13 and its 5th term is 25. What is its 17th term.
(a) 69
(b) 73
(c) 77
(d) 81
Solution:
(b) 73
T2 = a + d = 13 ...(i)
T5 = a + 4d = 25 ...(ii)
On subtracting (i) from (ii), we get:
⇒ 3d = 12
⇒ d = 4
On putting the value of d in (i), we get:
⇒ a + 4= 13
⇒ a = 9
Now, T17 = a +16d = 9 + 16 ⨯ 4 = 73
Hence, the 17th term is 73.
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