Question:
The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm−1. Calculate its molar conductivity.
Solution:
Given,
κ = 0.0248 S cm−1
c = 0.20 M
$\therefore$ Molar conductivity, $\Lambda_{m}=\frac{\kappa \times 1000}{\mathrm{c}}$
$=\frac{0.0248 \times 1000}{0.2}$
= 124 Scm2mol−1
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