The correct electronic configuration and spin-

Question:

The correct electronic configuration and spinonly magnetic moment $(B M)$ of $G d^{3+}(Z=64)$, respectively, are

  1. $[\mathrm{Xe}] 5 \mathrm{f}^{7}$ and $8.9$

  2. $[\mathrm{Xe}] 4 \mathrm{f}^{7}$ and $7.9$

  3. $[\mathrm{Xe}] 5 \mathrm{f}^{7}$ and $7.9$

  4. $[\mathrm{Xe}] 4 \mathrm{f}^{7}$ and $8.9$


Correct Option: , 2

Solution:

Electronic configuration of $\mathrm{Gd}^{3+}$ is

${ }_{64} \mathrm{Gd}^{3+}=[\mathrm{Xe}] 4 \mathrm{f}^{7}$

$\mathrm{Gd}^{3+}$ having 7 unpaired electrons.

Magnetic moment $(\mu)=\sqrt{\mathrm{n}(\mathrm{n}+2)}$ B.M.

$\mu=\sqrt{7(7+2)}$ B.M.

$=7.9$ B.M.

$\mathrm{n} \Rightarrow$ Number of unpaired electrons.

 

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