The crystal Field stabilization Energy (CFSE) of

Question:

The crystal Field stabilization Energy (CFSE) of $\left[\operatorname{CoF}_{3}\left(\mathrm{H}_{2} \mathrm{O}\right)_{3}\right]\left(\Delta_{0}<\mathrm{P}\right)$ is :-

  1. $-0.8 \Delta_{0}$

  2. $-0.4 \Delta_{0}+\mathrm{P}$

  3. $-0.8 \Delta_{0}+2 \mathrm{P}$

  4. $-0.4 \Delta_{0}$


Correct Option: , 4

Solution:

$\left[\mathrm{CoF}_{3}\left(\mathrm{H}_{2} \mathrm{O}\right)_{3}\right] \quad \Delta_{0}<\mathrm{P}$

Means all ligands behaves as weak field ligands

$=[-0.4 \times 4+0.6 \times 2] \Delta_{0}$

$=[-1.6+1.2] \Delta_{0}$

$=\left[-0.4 \Delta_{0}\right]$

 

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