Question:
The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of the electron is ve = c/100. Then
(a) Ee/Ep = 10-4
(b) Ee/Ep = 10-2
(c) Pe/mec = 10-2
(d) Pe/mec = 10-4
Solution:
The correct answers are
(b) Ee/Ep = 10-2
(c) Pe/mec = 10-2
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