The following observation s have been arranged in ascending order.

Total number of observation in the given data is 10 (even number). So median of this data will be mean of $10 / 2 \mathrm{i}$. $e$, $5^{\text {th }}$ observation and $10 / 2+1$ i. e, 6 the observation. So,

Median of data $=\frac{5^{\text {th }} \text { observation }+6^{\text {th }} \text { observation }}{2}$

$\Rightarrow 63=\frac{x+x+2}{2}$

$\Rightarrow 63=\frac{2 x+2}{2}$

⇒ 63 = x + 1

⇒ x = 62